# Write an equation in standard form for the line described to a tee

First, standard form allows us to write the equations for vertical lines, which is not possible in slope-intercept form. In particular, our book would not have cleared the fraction in example 4. This example demonstrates why we ask for the leading coefficient of x to be "non-negative" instead of asking for it to be "positive".

This gives us the standard form: Now, we must convert to standard form.

However it will become quite useful later. We can move the x term to the left side by adding 2x to both sides. First, we need to move the x-term to the left side of the equation so we add 3x to both sides. We need the x-term to be positive, so multiply the equation by -1 to get our answer: I have seen it where fractions have been allowed to stay in standard form.

We have seen that we can transform slope-intercept form equations into standard form equations.

For horizontal lines, that coefficient of x must be zero. It is a very useful skill that will come in handy later in the year. This is done by subtracting mx from both sides. Discussion The standard form of a line is just another way of writing the equation of a line.

Any line parallel to the given line must have that same slope. Doing this gives us: Finally, we must get rid of the fraction so, we clear the fraction by multiplying by the common denominator of all of the terms which is 4. Substitution gives us the equation of the line as: This topic will not be covered until later in the course so we do not need standard form at this point.

There are a number of reasons. Recall that the slope-intercept form of a line is: To change this into standard form, we start by moving the x-term to the left side of the equation. Again, start by moving the x-term to the left. However, for our class, we will clear the fractions.

Let us look at the typical parallel line problem. Write the equation of the line: First, we have to write the equation of a line using the given information. Here, the coefficient of the x-term is a positive integers and all other values are integers, so we are done.

A third reason to use standard form is that it simplifies finding parallel and perpendicular lines. The authors would have left the answer as: Standard Form of a Line by: Remember that vertical lines have an undefined slope which is why we can not write them in slope-intercept form.

The coefficient of the x-term should be a positive integer value, so we multiply the entire equation by an integer value that will make the coefficient positive, as well as, all of the coefficeints integers.A) Write an equation in standard from and in slope intercept form for the line described through (3,10), parallel y= -4 B) Write an equation in sloper intercept form and in standard form for the line passing through (2,6) and perpendicular to x = You can put this solution on YOUR website!

Write the slope intercept form of the equation of the line described.

through: (-4,0), parallel to y=3x/ Step 1. We can find the slope by recognizing that parallel lines have the same slope. Write an equation for the line described in standard form. through (±1, 7) and (8, ±2) 62/87,21 First, find the slope.

Write the equation in point-slope formula and change to standard form.

through (±4, 3) with y-intercept 0 62/87,21 First, find the slope of the line. Use the point-slope form to. Write the equation of the line, in slope-intercept form, that passes through (6,-4) and is perpendicular to the line y=3x+2.

y=-1/3x-2 A drama club goes to the movies. Write the equation of the line containing the point (15,5) with a slope of 2/3. y=2/3x-5 Write the equation of the line containing the point (-8,-9) with a slope of 3/2. Write the standard form of the equation of the line described.

9) through: (,), parallel to y x 10) through: (,), parallel to y x.

Write an equation in standard form for the line described to a tee
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